Mercurial > prosody-modules
view mod_support_room/mod_support_room.lua @ 6029:cc665f343690
mod_firewall: SUBSCRIBED: Flip subscription check to match documentation
The documentation claims that this condition checks whether the recipient is
subscribed to the sender.
However, it was using the wrong method, and actually checking whether the
sender was subscribed to the recipient.
A quick poll of folk suggested that the documentation's approach is the right
one, so this should fix the code to match the documentation.
This should also fix the bundled anti-spam rules from blocking presence from
JIDs that you subscribe do (but don't have a mutual subscription with).
| author | Matthew Wild <mwild1@gmail.com> |
|---|---|
| date | Fri, 22 Nov 2024 13:50:48 +0000 |
| parents | f72aa8840042 |
| children |
line wrap: on
line source
local mm = require "core.modulemanager"; local st = require "util.stanza"; local jid_host, jid_prep = import("util.jid", "host", "prep"); local invite_to_room = assert(jid_prep(module:get_option_string(module.name)), "The option " .. module.name .. " must be set"); local inviter = module:get_option_string(module.name .. "_inviter", module.host); local invite_reason = module:get_option_string(module.name .. "_reason"); module:hook("user-registered", function (event) local user_jid = event.username .. "@" .. event.host; local muc = mm.get_module(jid_host(invite_to_room), "muc"); if not muc then module:log("error", "There is no MUC service '%s'", jid_host(invite_to_room)); return; end local room = muc.get_room_from_jid(invite_to_room); if room then room:set_affiliation(true, user_jid, "member", invite_reason, { reserved_nickname = event.username }); -- Invite them to the room too module:send(st.message({ from = inviter, to = user_jid }) :tag("x", { xmlns = "jabber:x:conference", jid = invite_to_room, reason = invite_reason }):up()); else module:log("error", "The room %s does not exist, can't invite newly registered user", invite_to_room); end end);
