view mod_proxy65_whitelist/mod_proxy65_whitelist.lua @ 6029:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parents f96b947303a2
children
line wrap: on
line source

local allowed_streamhosts = module:get_option_set("allowed_streamhosts", {}); -- eg proxy.eu.jabber.org

if module:get_option_boolean("allow_local_streamhosts", true) then
	for hostname, host in pairs(hosts) do
		if host.modules.proxy65 then
			allowed_streamhosts:add(hostname);
		end
	end

	module:hook_global("host-activated", function (host)
		if hosts[host].modules.proxy65 then
			allowed_streamhosts:add(host);
		end
	end);
end

local function filter_streamhosts(tag)
	if tag.name == "streamhost" and not allowed_streamhosts:contains(tag.attr.jid) then
		return nil;
	end
	return tag;
end

module:hook("iq/full", function (event)
	local stanza = event.stanza;
	if stanza.attr.type == "set" then
		local payload = stanza:get_child("query", "http://jabber.org/protocol/bytestreams");
		if payload then
			payload:maptags(filter_streamhosts);
		end
	end
end, 1);