view mod_jid_prep/mod_jid_prep.lua @ 6029:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parents 99cb06b31ae8
children
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-- Run JIDs through stringprep processing on behalf of clients
-- http://xmpp.org/extensions/inbox/jidprep.html

local jid_prep = require "util.jid".prep;
local st = require "util.stanza";

local xmlns_prep = "urn:xmpp:jidprep:0";

module:add_feature(xmlns_prep);

function prep_jid(event)
	local stanza = event.stanza;
	local jid = jid_prep(stanza:get_child_text("jid", xmlns_prep));
	if not jid then
		return event.origin.send(st.error_reply(stanza, "modify", "jid-malformed"));
	end
	return event.origin.send(st.reply(stanza):tag("jid", { xmlns = xmlns_prep }):text(jid));
end


module:hook("iq/host/"..xmlns_prep..":jid", prep_jid);

module:depends("http");
module:provides("http", {
	route = {
		["GET /*"] = function (event, jid)
			return jid_prep(jid) or 400;
		end;
	}
});