Mercurial > prosody-modules
view mod_http_auth_check/mod_http_auth_check.lua @ 6029:cc665f343690
mod_firewall: SUBSCRIBED: Flip subscription check to match documentation
The documentation claims that this condition checks whether the recipient is
subscribed to the sender.
However, it was using the wrong method, and actually checking whether the
sender was subscribed to the recipient.
A quick poll of folk suggested that the documentation's approach is the right
one, so this should fix the code to match the documentation.
This should also fix the bundled anti-spam rules from blocking presence from
JIDs that you subscribe do (but don't have a mutual subscription with).
| author | Matthew Wild <mwild1@gmail.com> |
|---|---|
| date | Fri, 22 Nov 2024 13:50:48 +0000 |
| parents | 5ca6d53d3186 |
| children |
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-- HTTP Is User Valid -- By Nicolas Cedilnik <nicoco@nicoco.fr> local jid_prep = require "util.jid".prep; local jid_split = require "util.jid".split; local test_password = require "core.usermanager".test_password; local b64_decode = require "util.encodings".base64.decode; local saslprep = require "util.encodings".stringprep.saslprep; local realm = module:get_host() .. "/" .. module:get_name(); module:depends"http"; local function authenticate (event, path) local request = event.request; local response = event.response; local headers = request.headers; if not headers.authorization then response.headers.www_authenticate = ("Basic realm=%q"):format(realm); return 401 end local from_jid, password = b64_decode(headers.authorization:match"[^ ]*$"):match"([^:]*):(.*)"; from_jid = jid_prep(from_jid); password = saslprep(password); if from_jid and password then local user, host = jid_split(from_jid); local ok, err = test_password(user, host, password); if ok and user and host then return 200 elseif err then return 401 end end end module:provides("http", { route = { GET = authenticate }; });
