view mod_http_auth_check/mod_http_auth_check.lua @ 6029:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parents 5ca6d53d3186
children
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-- HTTP Is User Valid
-- By Nicolas Cedilnik <nicoco@nicoco.fr>

local jid_prep = require "util.jid".prep;
local jid_split = require "util.jid".split;
local test_password = require "core.usermanager".test_password;
local b64_decode = require "util.encodings".base64.decode;
local saslprep = require "util.encodings".stringprep.saslprep;
local realm = module:get_host() .. "/" .. module:get_name();
module:depends"http";

local function authenticate (event, path)
	local request = event.request;
	local response = event.response;
	local headers = request.headers;
	if not headers.authorization then
		response.headers.www_authenticate = ("Basic realm=%q"):format(realm);
		return 401
	end
	local from_jid, password = b64_decode(headers.authorization:match"[^ ]*$"):match"([^:]*):(.*)";
	from_jid = jid_prep(from_jid);
	password = saslprep(password);
	if from_jid and password then
		local user, host = jid_split(from_jid);
		local ok, err = test_password(user, host, password);
		if ok and user and host then
			return 200
		elseif err then
			return 401
		end
	end
end

module:provides("http", {
	route = {
		GET = authenticate
	};
});