view mod_auto_answer_disco_info/mod_auto_answer_disco_info.lua @ 6029:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parents 05c74210c007
children
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module:depends("cache_c2s_caps");

local st = require "util.stanza";

local function disco_handler(event)
	local stanza, origin = event.stanza, event.origin;
	local query = stanza.tags[1];
	local to = stanza.attr.to;
	local node = query.attr.node;

	local target_session = prosody.full_sessions[to];
	if target_session == nil then
		return;
	end

	local disco_info = target_session.caps_cache;
	if disco_info ~= nil and (node == nil or node == disco_info.attr.node) then
		local iq = st.reply(stanza);
		iq:add_child(st.clone(disco_info));
		local log = origin.log or module._log;
		log("debug", "Answering disco#info on the behalf of %s", to);
		module:send(iq);
		return true;
	end
end

module:hook("iq/full", function(event)
	local stanza = event.stanza;
	if stanza.attr.type == "get" then
		if stanza:get_child("query", "http://jabber.org/protocol/disco#info") then
			return disco_handler(event);
		end
	end
end, 1);