view mod_admin_notify/mod_admin_notify.lua @ 6029:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parents 44e18454e1e0
children
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local it = require "util.iterators";
local jid = require "util.jid";
local set = require "util.set";
local st = require "util.stanza";

local roles_store = module:open_store("roles", "map");
local config_admins = module:get_option_inherited_set("admins", {}) / jid.prep;

local function append_host(username)
	return username.."@"..module.host;
end

local function get_admins()
	local role_admins = roles_store:get_all("prosody:admin") or {};
	local admins = config_admins + (set.new(it.to_array(it.keys(role_admins))) / append_host);
	return admins;
end

function notify(text) --luacheck: ignore 131/notify
	local base_msg = st.message({ from = module.host })
		:text_tag("body", text);
	for admin_jid in get_admins() do
		local msg = st.clone(base_msg);
		msg.attr.to = admin_jid;
		module:send(msg);
	end
end