annotate mod_auth_external_insecure/examples/python/prosody-auth-example.py @ 6029:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parents f84ede3e9e3b
children
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1 #!/usr/bin/env python2
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2
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3 import sys
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4
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5 def auth(username, password):
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6 if username == "someone":
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7 return "1"
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8 return "0"
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9
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10 def respond(ret):
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11 sys.stdout.write(ret+"\n")
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12 sys.stdout.flush()
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13
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14 methods = {
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15 "auth": { "function": auth, "parameters": 2 }
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16 }
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17
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18 while 1:
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19 line = sys.stdin.readline().rstrip("\n")
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20 method, sep, data = line.partition(":")
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21 if method in methods:
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22 method_info = methods[method]
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23 split_data = data.split(":", method_info["parameters"])
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24 if len(split_data) == method_info["parameters"]:
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25 respond(method_info["function"](*split_data))
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26 else:
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27 respond("error: incorrect number of parameters to method '%s'"%method)
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28 else:
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29 respond("error: method '%s' not implemented"%method)